Java Code Example: pattern reverse

This is another example of a Java program that prints a pattern of numbers. The program is similar to the previous example, but it prints the numbers in reverse order for each row.

Here’s a breakdown of how the program works:

• The outer loop iterates over the rows of the pattern, from 1 to 8.
• The inner loop iterates over the columns of the pattern, from 8 to the current row number i.
• For each position in the pattern, the value of i is printed using the System.out.print() method.
• After printing all the values in the current row, a newline character is printed using the System.out.println() method to move to the next row.

class Pattern {
	public static void main(String[] args) {
		int i, j;
		
		for (i = 1; i <= 8; i++) {
			for (j = 8; j >= i; j--) {
				System.out.print(i);
			}
			System.out.println();
		}
	}
}

Output

11111111
2222222
333333
44444
5555
666
77
8

As you can see, the pattern is the same as the previous example, but the numbers are printed in reverse order for each row.