This code defines a function called decToHex()
that converts a decimal (base-10) number to its hexadecimal (base-16) representation, omitting the ‘0x’ prefix. The function takes an integer x
as input, converts it to a hexadecimal string using the hex()
function, then splits this string at ‘x’ and returns the last part of the split array, which is the hexadecimal value without the prefix. The print
statement calls this function with the argument 140
, and prints the hexadecimal representation of 140
, which is 8c
.
Detailed Breakdown:
decToHex(x)
converts a decimal number x
to a hexadecimal string.hex(x)
to generate the hexadecimal string, then employs split('x')
to discard the '0x'
prefix.140
as 8c
.def decToHex(x):
return hex(x).split('x')[-1]
print(decToHex(140))
8c
The function starts by using the built-in hex
function in Python to convert the decimal number x
to its equivalent hexadecimal representation. The hexadecimal representation is returned as a string with the prefix 0x
attached to it, e.g. 0x8c
for the decimal number 140.
Next, the string is split using the split
method with the argument 'x'
. This will result in a list with two elements: ['0', '8c']
. The second element of the list, '8c'
, is the hexadecimal representation without the 0x
prefix. This is obtained using the [-1]
list indexing syntax.
Finally, the function returns the hexadecimal representation without the prefix as the output.
When the code is executed, it calls the decToHex
function with the argument 140
. This will result in the hexadecimal representation of 140, '8c'
, being printed to the console.