This Python code checks if a given number is a neon number. A neon number is a number for which the sum of the digits of its square equals the original number. The program prompts the user to input a number, calculates its square, and then sums the digits of the square. Finally, it compares this sum to the original number and prints whether the number is a neon number or not.

```
# Initialize the sum variable to 0
sum = 0
# Prompt the user to enter a number
print("Enter the number to check:")
# Read the input and convert it to an integer
num = int(input())
# Calculate the square of the number
square = num * num
# Loop to sum the digits of the square
while (square != 0):
# Extract the last digit of the square
digit = square % 10
# Add the digit to the sum
sum = sum + digit
# Remove the last digit from the square
square = square // 10
# Check if the original number is equal to the sum of the digits of its square
if (num == sum):
# If true, print that the number is a neon number
print(str(num) + " is a neon number.")
else:
# If false, print that the number is not a neon number
print(str(num) + " is not a neon number.")
```

```
Enter a number to check for neon number:
9
9 is a neon number.
Enter a number to check for neon number:
30
30 is not a neon number.
```

```
sum = 0
print("Enter the number to check:")
num = int(input())
square = num * num
```

**Initialize**:`sum`

`sum = 0`

initializes a variable`sum`

to 0. This variable will be used to store the sum of the digits of the square of the number.**Prompt for Input**:`print("Enter the number to check:")`

prints a message asking the user to enter a number.**Read Input**:`num = int(input())`

reads the user input, converts it to an integer, and assigns it to the variable`num`

.**Calculate Square**:`square = num * num`

calculates the square of`num`

and assigns the result to the variable`square`

.

```
while (square != 0):
digit = square % 10
sum = sum + digit
square = square // 10
```

**While Loop**:`while (square != 0):`

initiates a loop that continues as long as`square`

is not equal to 0. This loop extracts and sums the digits of`square`

.**Extract Last Digit**:`digit = square % 10`

extracts the last digit of`square`

by taking the remainder of`square`

divided by 10. This digit is stored in`digit`

.**Add Digit to Sum**:`sum = sum + digit`

adds the extracted digit`digit`

to the variable`sum`

.**Remove Last Digit**:`square = square // 10`

removes the last digit from`square`

by performing integer division by 10. This effectively shifts all digits of`square`

one place to the right.

```
if (num == sum):
print(str(num) + " is a neon number.")
else:
print(str(num) + " is not a neon number.")
```

**Comparison**:`if (num == sum):`

checks if the original number`num`

is equal to the sum of the digits of its square.**Print Result**:- If
`num`

is equal to`sum`

, the code executes`print(str(num) + " is a neon number.")`

, printing that`num`

is a neon number. - If
`num`

is not equal to`sum`

, the code executes`print(str(num) + " is not a neon number.")`

, printing that`num`

is not a neon number.

- If

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