This is a Python function `crossSum`

that calculates the cross sum of a given number `n`

. The cross sum is calculated as the sum of its digits.

```
def crossSum(n):
total = 0
while 0 != n:
total = int(total + (n % 10))
n = n / 10
return total
print(crossSum(123))
```

`6`

This code snippet defines a function to calculate the cross sum (also known as the digit sum) of a given integer. Here’s a detailed explanation of how the code works:

`crossSum(n)`

```
def crossSum(n):
total = 0
while 0 != n:
total = int(total + (n % 10))
n = n / 10
return total
```

**Purpose**: This function calculates the sum of the digits of the integer`n`

.**Parameter**: The function takes one parameter`n`

, which is the integer whose digits are to be summed.**Initialization**:`total`

is initialized to 0. This variable will hold the running total of the sum of the digits.

**While Loop**:- The loop continues as long as
`n`

is not equal to 0. - Inside the loop:
`n % 10`

gives the last digit of`n`

. For example, if`n`

is 123,`n % 10`

will be 3.- This last digit is added to
`total`

. The`int`

function ensures that`total`

remains an integer. `n = n / 10`

removes the last digit from`n`

. However, this operation should be`n = n // 10`

to ensure that`n`

becomes an integer after the division. Using`n = n / 10`

converts`n`

to a float, which can cause issues in subsequent iterations. This is likely a bug in the code.

- The loop continues as long as
**Return Value**: After the loop completes, the function returns the value of`total`

, which is the sum of the digits of the original`n`

.

`print(crossSum(123))`

**Function Call and Output**:- The
`crossSum`

function is called with the argument`123`

. - The result, which is the sum of the digits of
`123`

(i.e., 1 + 2 + 3 = 6), is printed.

- The

To ensure that the function works correctly with integer division, the `n = n / 10`

statement should be corrected to `n = n // 10`

. Here is the corrected version:

```
def crossSum(n):
total = 0
while 0 != n:
total = int(total + (n % 10))
n = n // 10 # Use integer division to avoid converting to float
return total
print(crossSum(123)) # Output should be 6
```

This is a Python function `crossSum`

that calculates the cross sum of a given number `n`

. The cross sum is calculated as the sum of its digits.

```
def crossSum(n):
return n if n <= 9 else (n % 10) + int(crossSum(n / 10))
print(crossSum(555))
```

`15`

`crossSum(n)`

```
def crossSum(n):
return n if n <= 9 else (n % 10) + int(crossSum(n / 10))
```

**Purpose**: This function calculates the sum of the digits of the integer`n`

using recursion.**Parameter**: The function takes one parameter`n`

, which is the integer whose digits are to be summed.**Base Case**:- The function checks if
`n`

is less than or equal to 9 (i.e.,`n`

is a single-digit number). - If
`n`

is a single-digit number, it simply returns`n`

.

- The function checks if
**Recursive Case**:- If
`n`

is greater than 9, the function performs two main operations:- It calculates
`n % 10`

, which gives the last digit of`n`

. - It makes a recursive call to
`crossSum`

with the integer division result of`n / 10`

(removing the last digit of`n`

). Note: The use of`n / 10`

here should be`n // 10`

to ensure integer division. - The sum of these two values is returned. The recursive call continues until
`n`

is reduced to a single-digit number.

- It calculates

- If
**Return Value**: The function returns the sum of the digits of`n`

.

`print(crossSum(555))`

**Function Call and Output**:- The
`crossSum`

function is called with the argument`555`

. - The result, which is the sum of the digits of
`555`

(i.e., 5 + 5 + 5 = 15), is printed.

- The

To ensure correct integer division, the `n / 10`

statement should be corrected to `n // 10`

. Here is the corrected version:

```
def crossSum(n):
return n if n <= 9 else (n % 10) + int(crossSum(n // 10))
print(crossSum(555)) # Output should be 15
```

Let’s break down the recursive calls for `crossSum(555)`

:

**First Call**:`crossSum(555)`

`555`

is greater than 9, so it computes`(555 % 10) + crossSum(555 // 10)`

.`555 % 10`

is`5`

.- Recursive call:
`crossSum(555 // 10)`

which is`crossSum(55)`

.

**Second Call**:`crossSum(55)`

`55`

is greater than 9, so it computes`(55 % 10) + crossSum(55 // 10)`

.`55 % 10`

is`5`

.- Recursive call:
`crossSum(55 // 10)`

which is`crossSum(5)`

.

**Third Call**:`crossSum(5)`

`5`

is less than or equal to 9, so it returns`5`

.

Combining the results of these calls:

`crossSum(555)`

=`5 + crossSum(55)`

`crossSum(55)`

=`5 + crossSum(5)`

`crossSum(5)`

=`5`

Thus, the total sum is `5 + 5 + 5 = 15`

.

The function will correctly print `15`

for `crossSum(555)`

.

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